Please help me with this question
NO SPAM
Answers
Answer:
Explanation:
the points A and B for the group of resistors in the drawing. Use R1 = 6 Ω, R2 = 11 Ω, and R3 = 6 Ω.
Circuit Analysis:
Circuit analysis can be done by combining resistors into what is called equivalent resistors. Equivalent resistors are not real resistors, but represent the mathematical equivalent of two or more resistors. The battery in a circuit wouldn't feel the difference between the original resistor arrangement and the equivalent resistance.
Answer and Explanation:
The equivalent resistance is about 29 Ω.
The circuit we are dealing with is:
circuitab
The first step is to combine the 11 Ω and 6 Ω resistors. They are in series so their equivalent resistance (R11,6) is the sum of their resistances, which equals 17 Ω.
Combining the 9 Ω and 6 Ω resistors is next. They are in parallel so we add their inverses and then inverse that result.
1
R
9
,
6
=
1
9
+
1
6
R
9
,
6
=
3.6
Ω
R11,6 and R9,6 are in parallel.
1
R
9
,
6
,
11
,
6
=
1
3.6
+
1
17
R
9
,
6
,
11
,
6
=
2.97
Ω
The three remaining resistors are in series, so all we have to do is sum them to get the equivalent resistance of the circuit.
R
e
q
,
a
→
b
=
R
20
+
R
1
+
R
9
,
6
,
11
,
6
R
e
q
,
a
→
b
=
20
+
6
+
2.97
R
e
q
,
a
→
b
=
28.97
Ω
≈
29
Ω