Question

please help me with this question....... please its urgent....

Answer 1

ax²-5x+c=0

Given, sum of zeroes = 10

∴-b/a=10

ie, -(-5)/a=10

⇒a=5/10=1/2

Also, product=10

⇒c/a=10

⇒c=5

∴a=1/2 and c=5

Answer 2

★ Solution :-

Given ,

• Sum of zeroes = 10
• Product of zeroes = 10
• Quadratic polynomial = ax² - 5x + c

We need to find ,

• a
• c

As we know that ,

• Sum of roots = - b/a

• Product of roots = c/a

Where

• b → coefficient of x = - 5
• a → coefficient of x² = a
• c → constant term = c

Substituting the known values we have

Sum of roots = - b/a

→ 10 = -(-5)/a

[°.° Given that sum of roots = 10 ]

→ 10a = 5

→ a = 5/10

→ a = 1/2

Product of roots = c/a

→ 10 = c/(½)

→ 10 = 2c/1

→ 2c = 10

→ c = 10/2

→ c = 5

Hence , a = 1/2 & c = 5