Question

Please help me with this question with explanation, will mark it as the brainliest

Answer 1

Answer:

sum of all angles of triangle = 180°

so, PQR + QRP + RPQ = 180°

47° + 52° + RPQ = 180°

99° + RPQ = 180°

RPQ = 180°- 99°

RPQ = 81°

hope it helps u

Answer 2

REQUIRED ANSWER:-

• (c) 81°

SOLUTION :-

We are supposed to use the angle sum property of a triangle i.e sum of all the three angles of a triangle is equivalent to 180°

$\\ \quad \mapsto \quad \sf {47}^{0} + {57}^{0} +∠ QPR = {180}^{0}$

$\\ \quad \mapsto \quad \sf {99}^{0} + ∠ QPR = {180}^{0}$

$\\ \quad \mapsto \quad \sf ∠ QPR = {180}^{0} - {99}^{0}$

$\\ \quad \mapsto \quad \therefore \boxed{\boxed{\sf ∠ QPR = {81}^{0} }} \bigstar$

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