Please help me with this sum
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Answer:
OA+OB+OC+OD>AC+BD
Step-by-step explanation:
Given:- ABCD is a quadrilateral. O is a point inside the quadrilateral ABCD.
To prove:- OA+OB+OC+OD>AC+BD
Construction : Join OA,OB,OC and OD. Also, join AC and BD.
Proof:- As we know that the sum of any two sides of a triangle is greater than the third side.
Therefore,
In △BOD,
OB+OD>BD.....(1)
Similarly
In △AOC,
OA+OC>AC.....(2)
Adding eq
n
(1)&(2), we have
OB+OD+OA+OC>BD+AC
∴OA+OB+OC+OD>AC+BD
Hence proved.
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Answer is attached above.
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