Question

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Answer 1

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$2x - 3y = 12$

$- 3y = 12 - 2x$

$y = \frac{2x - 12}{3}$

At x - axis, y = 0 ; x= 12/6

x = 6

Hence the given equation interests x - axis at point (6, 0)

At y - axis,

x = 0 ; y = -12/3

y = -4

Hence the given equation interests y - axis at point (0, -4)

Answer 2

2x - 3y = 122x−3y=12

- 3y = 12 - 2x−3y=12−2x

y = \frac{2x - 12}{3}y=

3

2x−12

At x - axis, y = 0 ; x= 12/6

x = 6

Hence the given equation interests x - axis at point (6, 0)

At y - axis,

x = 0 ; y = -12/3

y = -4

Hence the given equation interests y - axis at point (0, -4)