please help me x2 + 6x +5
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x² + 6x + 5
=> x² + (5 + 1)x + 5
=> x² + 5x + x + 5
=> x(x + 5) + 1(x +5)
=> (x + 5)(x + 1)
I hope this will help you
(-:
=> x² + (5 + 1)x + 5
=> x² + 5x + x + 5
=> x(x + 5) + 1(x +5)
=> (x + 5)(x + 1)
I hope this will help you
(-:
Manwil:
so the final solution is: x=-5 or x=-1
It can't be
x =-5 or x = -1 only when the equation is equal to 0
you are right
But here, equation is not equal to 0,so x can't be considered as - 5 or -1
(-;
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