Question

please help me

(y+1/3) - (y-1/2) = (1+2y/3)

Answer 1

Answer:

answer=-6

Step-by-step explanation:

Firstly we have to take all y one side

and numerals another side

by solving it we get y=-6

Answer 2

ANSWER:

Given:

• (y + 1)/3 - (y - 1)/2 = (1 + 2y)/3

To Find:

• Value of y

Solution:

We are given that,

$\implies\dfrac{y+1}{3}-\dfrac{y-1}{2}=\dfrac{1+2y}{3}$

Taking LCM,

$\implies\dfrac{y+1}{3}-\dfrac{y-1}{2}=\dfrac{1+2y}{3}$

$\implies\dfrac{2(y+1)-3(y-1)}{6\!\!\!/{_\:2}}=\dfrac{1+2y}{3\!\!\!/}$

$\implies\dfrac{2y+2-3y+3}{2}=2y+1$

$\implies\dfrac{5-y}{2}=2y+1$

Transposing 2 to RHS,

$\implies5-y=2(2y+1)$

$\implies5-y=4y+2$

Transposing y to RHS, and 2 to LHS,

$\implies5-2=4y+y$

$\implies3=5y$

$\implies5y=3$

Transposing 5 to RHS,

$\implies\bf y=\dfrac{3}{5}$