Question

please help meplease help me
do this sums as soon as possible
no wrong answer please​

Answer 1

Step-by-step explanation:

${( \sqrt{6} - 2 \sqrt{3}) }^{2} \\ {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ {( \sqrt{6}) }^{2} + {(2 \sqrt{3}) }^{2} - 2 \times \sqrt{6} \times 2 \sqrt{3} \\ 6 + 12 - 12 \sqrt{2} \\ 18 - 12 \sqrt{2} \\ x = 18 \: \: \: \: y = - 12 \: \: \: z = \sqrt{2}$

Hope you get your answer