Question

please help my exam is there

Answer 1

Perimeter:

→ Circumference of semicircle = 1/2 * π * d

1. Consider semicircle ALC:

⇒ 1/2 * 22/7 * 7 = 11 m

2. Consider semicircle CG:

⇒ 1/2 * 22/7 * (7 + 7 + 3.5) = 27.5 m

3. Consider semicircle EFG:

⇒ 1/2 * 22/7 * 7 = 11 m

4. Consider semicircle EHB:

⇒ 1/2 * 22/7 * 7 = 11 m

5. Consider semicircle ADB:

⇒ 1/2 * 22/7 * (7 + 3.5) = 16.5 m

Perimeter of figure = 11 + 27.5 + 11 + 11 + 16.5 = 77 m

Area:

→ Area of semicircle = π * r² / 2

1. Consider shaded figure of semicircle ADB:

⇒ Area of ABD - Area of ALC

⇒ (22/7 * (5.25)² / 2 ) - (22/7 * (3.5)² /2 )

⇒ 43.3125 - 19.25 = 24.0625 m²

2. Consider shaded figure of semicircle CG:

⇒ Area of CG - Area of BHE

⇒ (22/7 * (8.75)² / 2) - (22/7 * (3.5)² / 2)

⇒ 120.3125 - 19.25 = 101.0625

3. Consider semicircle EFG:

⇒ 22/7 * (3.5)² / 2 = 19.25

Area of figure = 24.0625 + 101.0625 + 19.25 = 144.375 m²

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