Question

please help need answer ASAP$\cube{81} + \cube{-192} \cube{375} /\cube{24}$

Answer 1

Answer:

$\frac{\sqrt[3]{81}+\sqrt[3]{-192}+\sqrt[3]{375} }{ \sqrt[3]{24}}$

solve separately

≅$\frac{4.32+-5.76+7.21}{2.8}$

≅ 5.77/2.8

≅ 2.06