Question

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Answer 1

Step-by-step explanation:

answer in the attachment

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Answer 2

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$\frac{4 - (4 - 3y)}{2y - (3 + 4y)} = \frac{1}{5}$

$\frac{4 - 4 + 3y}{2y - 3 - 4y} = \frac{1}{5}$

$\frac{3y}{ - 2y - 3} = \frac{1}{5}$

$5(3y) = - 2y - 3$

$15y + 2y = - 3$

$17y = - 3$

$y = \frac{ - 3}{17}$