please help physics class 11 and spammers will be reported
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Answers
Answered by
4
Answer
600m
Solution
Given
velocity of car A = 20m/s
velocity of car B = 10m/s
Acceleration of car A = 1m/s^2
Acceleration of car B = 2m/s^2
To Find
Distance between A and B
Formula of distance
S = ut + 1 / 2 at^2
Distance of car A
S = 20t + 1 / 2 t^2 ......... (1)
Distance of car B
S = 10t + t^2 .......... (2)
we know that A = B
=> 20t + 1 / 2 t^2 = 10t + t^2
=> 10t = t^2 - 1 / 2 t^2
=> 10t = t^2 / 2
=> t = 20 seconds
Put t = 20 seconds in equation (2)
we get
=> 10(20) + ( 20) ^2
=> 200 + 400
=> 600 m = ANSWER
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