Question

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Answer 1

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Answer 2

❏ Question:-

Refer to the questionar attachment :).

Find the area of the triangular prism,

❏ Solution:-

Here , Area of the Prism, is

$A_{prism}=A_{ABCJ}+A_{CDE}+A_{CEHJ}+A_{IHJ}+A_{EFGH}$

Now, ABCJ , CEHJ and EFGH are rectangles,

• $A_{ABCJ}=(11\times3)=33\:unit^2$

• $A_{CEHJ}=(11\times4)=44\:unit^2$

• $A_{EFGH}=(11\times5)=55\:unit^2$

Now, CDE and IHJ are right angled Triangle,

• $A_{CDE}=\frac{1}{2}\times base\times height$

$\implies A_{CDE}=\frac{1}{2}\times CE\times CD$

$\implies A_{CDE}=\frac{1}{\cancel2}\times\cancel4 \times 3$

$\implies A_{CDE}=6\:unit^2$

• $A_{IHJ}=\frac{1}{2}\times base\times height$

$\implies A_{IHJ}=\frac{1}{2}\times HJ \times IJ$

$\implies A_{IHJ}=\frac{1}{\cancel2}\times\cancel 4 \times 3$

$\implies A_{IHJ}=6\:unit^2$

$\therefore A_{prism}=A_{ABCJ}+A_{CDE}+A_{CEHJ}+A_{IHJ}+A_{EFGH}$

$\implies A_{prism}=(33+6+44+6+55)\:unit^2$

$\implies\boxed{ \large{A_{\red{prism}}=144\:unit^2}}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$