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if vectors a+2b and 5a-4b are perpendicular to each other and a and b are unit vectors. Find the angle between a and b.
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Answer:
HELLO THERE,
let A vector = a+2b
let B vector = 5a-4b
A.B = 0
therefore (a+2b).(5a-4b) = 0
expanding , a.5a - 4 a.b + 10 a.b - 8 b.b=0
since a.a and b.b = 1, ( bcoz a.a = 1.1.cos0)
5-8 + 6 a.b = 0
a.b = 1/2
ab cos(theta) = 1/2
THEREFORE, THETA = 60degrees or pi/3 radians.
the key in the question is the expansion because dot product follows distributive law
ShiyamGanesh:
Sorry, pls by mistake I wrote a.a and b.b is zero. it's is actually ONE
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