please help question no. 2 only
math
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34
- Factorize the equation
- Add 15 both side we get
- Take square root both side
- Compare the equation with where a = 1, b = 0, c = -15
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Answer:
t²–15
Factorize the equation
\tt \: t² – 15 = 0t²–15=0
Add 15 both side we get
\tt \: t² = 15t²=15
Take square root both side
\tt \: t= ± √15t=±√15
\begin{gathered} \sf \: First \: zero \: is \: √15 \\ \sf \: second \: zero \: is - √15\\ \sf \: Sum \: of \: zero \: √15 - √15 = 0\\ \sf \: Product \: of \: zero \: √15 x -√15 = -15\end{gathered}
Firstzerois√15
secondzerois−√15
Sumofzero√15−√15=0
Productofzero√15x−√15=−15
Compare the equation with \bold{at² + bt +c = 0}at²+bt+c=0 where a = 1, b = 0, c = -15
\begin{gathered} \bold{ \: Sum \: of \: zero \frac{ - b}{a} } \sf \: = -(0 \div 1) = 0 \\ \\ \bold{Product \: of \: zero = \frac{c}{a} } \sf \: = -15/1 = -15\end{gathered}
Sumofzero
a
−b
=−(0÷1)=0
Productofzero=
a
c
=−15/1=−15
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