Math, asked by poojahakke, 3 months ago

Please help resolve the 8th one

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Answered by vipashyana1
1

Answer:

 \frac{ 2x - \frac{3}{4} }{3x +  \frac{4}{5} }  =  \frac{1}{5}

 \frac{ \frac{8x - 3}{4} }{ \frac{15x + 4}{5} }  =  \frac{1}{5}

 \frac{8x - 3}{4}  \times  \frac{5}{15x + 4}  =  \frac{1}{5}

 \frac{5(8x - 3)}{4(15x + 4)} =  \frac{1}{5}

 \frac{40x - 15}{60x + 16} =  \frac{1}{5}

5(40x - 15) = 1(60x + 16)

200x - 75 = 60x + 16

200x - 60x = 16 + 75

140x = 91

x =  \frac{91}{140}  =  \frac{13}{20}

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