Please help, solve with explanation ASAP
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Hey
Here is your answer
C) AC^2 = AB^2 + BC^2
= (12)^2 + (36)^2
= 144 + 1296
=1440
Ac = 12√10cm
D) tan45 = 18/CG
1=18/CG
CG=18 cm
Sin 45 = FG/CF
1/√2 = 18/CF
CF=18√2 cm
E) CG+GD=31
18+GD=31
GD=31-18
GD=13 cm
Hence proved.
F) perimeter =12+31+18+13+18√2+36+12√10
= 114+18√2+12√10
Hope it helps you!
Here is your answer
C) AC^2 = AB^2 + BC^2
= (12)^2 + (36)^2
= 144 + 1296
=1440
Ac = 12√10cm
D) tan45 = 18/CG
1=18/CG
CG=18 cm
Sin 45 = FG/CF
1/√2 = 18/CF
CF=18√2 cm
E) CG+GD=31
18+GD=31
GD=31-18
GD=13 cm
Hence proved.
F) perimeter =12+31+18+13+18√2+36+12√10
= 114+18√2+12√10
Hope it helps you!
Answered by
1
by Pythagoras theorem...
a²+b²=c²
36²+12²
1296+144=1440
c²=1440
c=√1440
=38 approx.
a²+b²=c²
36²+12²
1296+144=1440
c²=1440
c=√1440
=38 approx.
ANMOLSEHGAL007:
pls mark it brianleist
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