Question

Please help
Solve X²+X+10√(x²+3x+16) = 2(20-X)

Answer 1

Answer:

x ∈ {0; -3}

Step-by-step explanation:

X²+X+10√(x²+3x+16) = 2(20-X)

<=> X²+3X-40+10√(x²+3x+16) = 0

<=> X²+3X + 16 +10√(x²+3x+16) - 56 = 0

√(x²+3x+16) = T ( T>0)

 T² + 10T -56 = 0 <=> T = 4(choose) or T= -14

=> √(x²+3x+16) = 4

<=> x²+3x+ 16 = 16

<=> x²+3x =0

<=> x=0 or x= -3