Math, asked by ssssssss77gg, 11 months ago

please help the math​

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Answered by ornitho118
0

Let

log_{m}(x)  = k

implies,

 {m}^{k}  = x

Now,

 {m}^{2 \times 3k}  =  {x}^{6}

Substituting x,

 {m}^{6k}  =  {m}^{k\times 6}

Thus

 {m}^{6k}  =  {m}^{6k}

Hence proved

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