Please help.
The number of atoms present in 0.5 g-atom of nitrogen is same as the atoms in
a. 12g of carbon
b. 32g of sulphur
c. 8g of oxygen
d. 24g of magnesium
Along with the answer please explain how , i really need it.
Answers
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Atomic mass of nitrogen = 14 g
Therefore, mass of 1 mole of nitrogen = 14g
Now, 1 mole = 6.022 x 1023 atoms
Since, 1 g-atom = 1 mole
0.5 g-atom = 0.5 moles
Therefore, no. of atoms in 0.5 moles of Nitrogen = 6.022 x 1023 x 0.5
= 3.011 x 1023
Now,
12 g carbon = 1 mole carbon
32 g sulphur = 1 mole sulphur
8 g oxygen = 0.5 mole oxygen
24 g magnesium = 1 mole magnesium
Number of atoms in 0.5 mole oxygen = = 3.011 x 1023
Hence, option (c) is correct.
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Therefore, mass of 1 mole of nitrogen = 14g
Now, 1 mole = 6.022 x 1023 atoms
Since, 1 g-atom = 1 mole
0.5 g-atom = 0.5 moles
Therefore, no. of atoms in 0.5 moles of Nitrogen = 6.022 x 1023 x 0.5
= 3.011 x 1023
Now,
12 g carbon = 1 mole carbon
32 g sulphur = 1 mole sulphur
8 g oxygen = 0.5 mole oxygen
24 g magnesium = 1 mole magnesium
Number of atoms in 0.5 mole oxygen = = 3.011 x 1023
Hence, option (c) is correct.
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