Please help.
The number of atoms present in 0.5 g-atom of nitrogen is same as the atoms in
a. 12g of carbon
b. 32g of sulphur
c. 8g of oxygen
d. 24g of magnesium
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Atomic mass of nitrogen = 14 g
Therefore, mass of 1 mole of nitrogen = 14g
Now, 1 mole = 6.022 x 1023 atoms
Since, 1 g-atom = 1 mole
0.5 g-atom = 0.5 moles
Therefore, no. of atoms in 0.5 moles of Nitrogen = 6.022 x 1023 x 0.5
= 3.011 x 1023
Now,
12 g carbon = 1 mole carbon
32 g sulphur = 1 mole sulphur
8 g oxygen = 0.5 mole oxygen
24 g magnesium = 1 mole magnesium
Number of atoms in 0.5 mole oxygen = = 3.011 x 1023
Hence, option (c) is correct.
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Therefore, mass of 1 mole of nitrogen = 14g
Now, 1 mole = 6.022 x 1023 atoms
Since, 1 g-atom = 1 mole
0.5 g-atom = 0.5 moles
Therefore, no. of atoms in 0.5 moles of Nitrogen = 6.022 x 1023 x 0.5
= 3.011 x 1023
Now,
12 g carbon = 1 mole carbon
32 g sulphur = 1 mole sulphur
8 g oxygen = 0.5 mole oxygen
24 g magnesium = 1 mole magnesium
Number of atoms in 0.5 mole oxygen = = 3.011 x 1023
Hence, option (c) is correct.
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