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get well answer and be happy...
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ANSWER:-
L.H.S
(1+tan^2 θ) cot θ/ cosec^2 θ
= sec^2 θ . cot θ/ cosec^2 θ
( we know, sec^2 θ - tan^2 θ = 1)
sec^2 θ = 1+ tan^2 θ
In next step we convert sec^2 into 1/cos^2, cot into cos/sin and cosec^2 into 1/ sin^2 respectively....
Hence we get,
[1/cos^2 θ × cos θ/sin θ]/ 1/ sin^2 θ
= 1/ sin θ . cos θ × sin^2 θ
= sin θ/ cos θ
= tan θ = R.H.S ( proved)
Hope it will help you ✌️
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