please help these sums
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which 1 will solve
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2) ( secx + tanx) (1-sinx) = secx-(secx × sinx) + tanx - (tanx × sinx) (obtained by multiplying the above terms ) we know that secx= 1/ cosx and tanx =sinx/cosx therefore
secx-(sinx/ cosx) +tanx-(sin^2x /cosx)
we know that sinx / cosx is tanx
= secx - tanx + tanx - sin^2x/cosx
= 1/cosx - sin^2x/cosx
= 1-sin^2x/ cosx is the final answer
i hope it was helpful
secx-(sinx/ cosx) +tanx-(sin^2x /cosx)
we know that sinx / cosx is tanx
= secx - tanx + tanx - sin^2x/cosx
= 1/cosx - sin^2x/cosx
= 1-sin^2x/ cosx is the final answer
i hope it was helpful
can you solve 1 and 3 sum if you can do it please solve
i will try
do u need it now
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