please help this is my last question of today's
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akshatrock111:
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1
sin90=1,cos45=sin45=1/√2
therefore, sin90-2xcos45xsin45
=1- (2 X 1/√2 X 1/√2)
=1-(2/2)
=1-1
=0
therefore, sin90-2xcos45xsin45
=1- (2 X 1/√2 X 1/√2)
=1-(2/2)
=1-1
=0
Answered by
0
(1) - 2 sin45 * sin45
1 - 2(1/√2)^2
1 - 2(1/2)
1 - 1
0
1 - 2(1/√2)^2
1 - 2(1/2)
1 - 1
0
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