please help this please ..........
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Answered by
6
I think, your diagram is not correct.
Point C should be on the circumference of the circle.
Answer:
∠BDC = 18°
Step-by-step explanation:
Given that OD is perpendicular of AB( diameter ),
So ∠AOD = ∠BOD = 90°
As OA and OD are the radius of the circle,
OA = OD
∴ ∠OAD = ∠ODA
= > ∠AOD + ∠OAD + ∠ODA = 180°
= > 90° + ∠OAD + ∠OAD = 180°
= > 2∠OAD = 180° - 90°
= > ∠OAD = 90° / 2
= > ∠OAD = 45°
= > ∠BAC + ∠DAC = 45°
= > ∠BAC + 27° = 45°
= > ∠BAC = 45° - 27°
= > ∠BAC = 18°
∠BAC = ∠BDC = 18° ( same segment, by theorem )
Therefore ∠BDC = 18°
Answered by
1
Answer:
it may be 18 degree......
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