please help to find out the factorization question no 8
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Step-by-step explanation:
- x^4+x^2y^2+y^4=0
- (x^2)^2+(y^2)x^2+y^4=0
by using quadratic formula
- a=1,b=y^2,c=y^4
- x^2=-y^2+_√(y^4-4y^4)/2
- x^2=-y^2+_y^2√-3/2
- x^2=(-y^2+iy^2√3)/2,x^2=(-y^2-¡y^2√3)/2
- x^2=y^2(-1+i√3)/2,y^2(-1-i√3)/2
- x=y√(-1+i√3)/√2,x=y√(-1-i√3)/√2
(x-y√(-1+i√3)/√2)(x-y√(-1-i√3)/√2)=0
pls mark my ans as brainiest
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