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p+q+r=180 degree 60+95=155 180-155 =25
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- AB||CD
- ∠APR = 95°
- ∠DRQ = 60°
- The value of ∠PRQ.
AB||CD and QR is a transversal.
∴ ∠PQR = ∠QRD = 60°ㅤ
──
Now, AB||CD and PR is a transversal.
∴ ∠DRP = ∠APR = 95°ㅤ
⇒ ∠QRD + ∠PRQ = 95°
⇒ 60° + ∠PRQ = 95°
⇒ ∠PRQ = (95° - 60°) = 35°
Hence, the value of ∠PRQ is 35°.
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