Question

please help to solve this question step by step.
those who will answer step by step I will mark them as a brainlist ​

Answer 1

Answer:

1. ₹315

2.₹10000

Step-by-step explanation:

Given:-

Internet (I) = ₹210 on the principal (P) of ₹3000 in a year.

So, interested rate (R) = 100 × 210/3000 = 7%.

Note:-

(for understanding you just think rate as interest earned on ₹100. So by dividing 210 by 3000 you get interest per 1 rupee and by multiplying you get interest per ₹100 which is rate.)

For principal amount of ₹4500 internet earned on rate of 7% in 1 year

= P×R×T/100 = 4500×7×1 /100 = ₹315

Now to have an interest of ₹700 we have,

700 = P×7×1 /100

==> P = 700×100 / 7 = ₹10000

Hence the required principal to get interest of ₹700 is ₹10000.

Answer 2

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$700 = \frac{P \times R \times T }{100} \\ 700 = \frac{P \times \: 7 \times 1 }{100} \\ P = \frac{700 \times 100}{7} \\ P = 1000$

$SI = \frac{PRT}{100}$

$\implies210= \frac{3000×R×T} {100}$

$\implies R= \frac{210}{30} = 7\%$

$\implies \: SI= \frac{PRT}{100}$

$\implies \: SI = \frac{4500 \times 7 \times 1}{100} \\ \implies \: SI=315/-$