Question

PLEASE HELP! two bodies of mass m1 and m2 (m2>m1) are connected by a light inextensible string which passes through a smooth fixed pulley. the instantaneous power delivered by an external agent 2 pull m1 with constant velocity v is: PLEASE TELL WHOLE SOLUTION

Answer 1

Answer:

Two bodies of mass m1 and m2 (m2>m1) are connected by a light inextensible string which passes through a smooth fixed pulley. The instantaneous power delivered by an external agent 2 pull m1 with constant velocity v is:

A

(m2-m1) g/v

B

(m2-m1) v/g

C

(m2-m1) gv

Correct Answer

D

(m1-m2) gv. Ans part c

Answer 2

Answer:

(m2 - m1)gv

Explanation:

a = dv/dt

as dv = 0

a = 0

F(net) = 0

T = m2g

T = F + m1g

m2g = F + m1g

F = (m2 - m1)g

P = F.v

  = (m2 - m1)gv

Thus the instantaneous velocity is (m2-m1)gv.

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