Physics, asked by Anonymous, 8 months ago

Please help urgent :(

A particle starts from rest and moves with a uniform acceleration of 2m/s2 for 12s and then it moves with a constant velocity for 4s. Later it slows down and comes to rest in 5s. Draw the velocity graph for the motion of the body and answer the following questions:

a. What is the maximum velocity attended by the body?
b. What is the distance travelled during this period of acceleration?
c. What is distance travelled when the body was moving with constant velocity?
d. What is the retardation of the body while slowing down?
e. What is the distance travelled by retarding?
f. What is the total distance travelled?​

Answers

Answered by nitashachadha84
0

a)  V at A :  25 m/sec

b) Area enclosed by triangle OAB =  1/2 * 25 * 5

= 62.5 m

c) area of ABCD = 25 * 4

= 100 m

d ) slope = (0-25)/5

= -5 m/sec²

e )  area of triangle DCE

= 62.5 m

f ) total area bounded between the OADE and time axis. = 62.5 + 100 + 62.5

= 230m

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Answered by ᎷíssGℓαмσƦσυs
0

Answer:

V at A : 25 m/sec

b) Area enclosed by triangle OAB = 1/2 * 25 * 5

= 62.5 m

c) area of ABCD = 25 * 4

= 100 m

d ) slope = (0-25)/5

= -5 m/sec²

e ) area of triangle DCE

= 62.5 m

f ) total area bounded between the OADE and time axis. = 62.5 + 100 + 62.5

= 230m

this is your answer ✔️✔️

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