Question

please help very urgent please solve it fast​

Answer 1

Given :-

• A cuboidal oil tin is 30 cm by 40 cm by 15 cm.

To find :-

• Find the cost of the tin required for making 20 tins if the cost of tin sheet is 20 per square metre.

Solution :-

★ 1m = 100cm ★

• Length of cuboidal oil tin = 30 cm = 30/100 = 0.3 m

• Breadth of cuboidal oil tin = 40 cm= 40/100 = 0.4 m

• Height of cuboidal oil tin = 50 cm = 50/100 = 0.5 m

Total surface area of cuboidal tin

→ 2(lb + bh + lh)

→ 2(0.3 × 0.4 + 0.4 × 0.5 + 0.3 × 0.5)

→ 2(0.12 + 0.2 + 0.15)

→ 2(0.32 + 0.15)

→ 2 × 0.47

→ 0.94 m²

Now, area of 20 tins

→ 20 × 0.94 = 18.8m²

The cost of tin sheet is 20 per square metre.

→ Total cost for making 20 tins

→ 18.8 × 20

→ Rs.376

Therefore,

• Total cost = Rs.376

Answer 2

ɢɪᴠᴇɴ:-

• A cuboidal oil tin with measures 30 cm by 40 cm by 15 cm

ᴛᴏ ғɪɴᴅ:-

• The cost of the tin required for making 20 tins if the cost of tin sheet is 20 per square

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:-

The cost of the tins depend upon their total surface area . It is given that a tin is in the shape of a cuboid such that:-

$\begin{lgathered}\begin{lgathered}\begin{lgathered}\tt {\pink{Given}}\begin{cases} \sf{\green{Length( l )= 30 cm}}\\ \sf{\blue{Breadth (b)= 40 cm}}\\ \sf{\orange{Height (h) = 50 cm.}}\end{cases}\end{lgathered} \:\end{lgathered}\end{lgathered}$

 Surface area of one tin:

$\begin{lgathered}= \sf \: 2(lb + bh + hl) \\ \\ \sf = 2(30 \times 40 + 40 \times 50 + 30 \times 50) {cm}^{2} \\ \\ = \sf2(1200 + 2000 + 1500) {cm}^{2} \\ \\ = \sf(2 \times 4700) {cm}^{2} = 9400 \: {cm}^{2} \\ \\\end{lgathered}$

$\begin{lgathered}\implies \sf \: 188000 \: {cm}^{2} \\ \\\end{lgathered}$

Now, we have to convert cm into m

$\begin{lgathered}\implies \sf \dfrac{188000}{10000} \: {m}^{2} \\ \\ \implies \sf 18.8 \: {m}^{2}\end{lgathered}$

Now,

Cost of 1 sq. m of tin sheet = Rs 20

∴ Cost of 18.8 m² of tin sheet =$\sf{20\times\:18.8}$=Rs376

Hence, the cost of making 20 tins = Rs 376

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