Please help!!!!!! whoever answers # correctly I will surely mark as #brainliest.....Its very much urgent Guys & Girls Please answer..........2. A car moving at.40 kmh is to be stopped by applying brakes in the next 4:0 min. If the car weighs 2000 kg, what average force must be applied on it ?
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Answer:
Initial velocity (u) = 40 kmph
Final velocity (v) = 0
Time (t) = 4 min = 1/15 hr
By 1 st eqn of motion
v = u + at
a = v-u/t
a = 0-40/1/15 = -60 km/ hr^2
since F = ma
F = 2000*-60
F= -120000 N
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