Math, asked by kartik10003, 1 month ago

please help will be a huge favour

Attachments:

Answers

Answered by roshni542
4

Answer:

 \sqrt{ {40}^{2 }  +  {9}^{2} }  ^{3}

 \sqrt{(40 \times 40) + (9 + 9)}  ^{3}

 \sqrt{1600 + 18}

 \sqrt{1618}  ^{3}

Answered by sonia007
1

firstly...40^2=1600

9^2=81

then add kro...1600+81=1681

ab underroot ka basically mtlb hota h ki...power=1/2...according to this

1681^1/2×3

hence,

1681^3/2

yahi hai aapka answer

Similar questions