Question

PLEASE HELP WILL MARK BRANLIEST
Please show work too^

Part A:
Solve the following system of equations algebraically showing your work:
3x+2y=4
4x+3y=7

Part B: Describe which method you used to solve the system. Explain why that method was better than the other methods.

Answer 1

Step-by-step explanation:

the best method is eliminating method because it is easiest one... beacause we have to multiply the equation to get the ans ...

3x + 2y = 4 --1eq

4x + 3y = 7 -- 2 eq

multiply 1 eq by 3 and 2 eq by 2 we get

9x + 6y = 12

8x + 6y = 4

-------------------

from here we get x = 8

put value of x in eq 1

24 + 2y = 4

2y = -20

y = -10

hoped u got the ans mark it as brainellist

Answer 2

AnsWer :

x = -2 and y = 5.

Solution :

We have,

Part A.

Solve the following system of equations.

• 3x + 2y = 4.
• 4x + 3y = 7.

Let try Substitution method.

$\tt3x + 2y = 4. - - - (1)$

$\tt4x + 3y = 7. - - - (2)$

$\rule{140}1$

Taking Equation (1)

$\tt\dashrightarrow 2y = 4 - 3x.$

$\tt\dashrightarrow y = \frac{4 - 3x}{2} - - - (3)$

$\rule{140}1$

Now, Putting equation 3 in equation 2, We get.

$\tt\dashrightarrow 4x + 3 \frac{ (4 - 3x)}{2} = 7.$

$\tt\dashrightarrow \frac{8x + 12 - 9x}{2} = 7.$

$\tt\dashrightarrow - x + 12 = 14.$

$\tt\dashrightarrow x = - 2.$

$\rule{140}1$

Putting the Value of x in equation 3.

$\tt\dashrightarrow y = \frac{4 - 3x}{2}$

$\tt\dashrightarrow y = \frac{4 - 3( - 2)}{2}$

$\tt\dashrightarrow y = \frac{4 + 6}{2}$

$\tt\dashrightarrow y = \frac{10}{2}$

$\tt\dashrightarrow y = 5.$

$\rule{140}1$

Verification :

• Taking Any equation form above,

$\tt3x + 2y = 4.$

• x = -2.
• y = 5.
• Above find.

$\tt\dashrightarrow 3( - 2) + 2(5) = 4.$

$\tt\dashrightarrow - 6 + 10 = 4.$

$\tt\dashrightarrow 4 = 4.$

$\rule{140}1$

Part B.

• Above Solution to find the value x and y / solve equation by substitution method,
• Substitution method define as, take any equation out of two then to try to find any variable respect to other one.
• Substitution method is better than other, we need to find out of two various then, substitute in other equation.
• Don't need any types of Multiplication in both Equation.

$\rule{140}1$

Some More method :

• Elimination method.
• Substitution method.
• Cross Multiplication method.