Question

Please help with math question...

Answer 1

$\frac{4}{k + 2} = \frac{x}{3} \\ 12 = x(k + 2) \\ 12 = kx+ 2x\\ 12 - 2x = kx \\ \frac{12 - 2x}{x} = k \\ k = \frac{12 - 2x}{x}$

Therefore, Option (a) is correct

Answer 2

$k = y \\ = > \frac{4}{y + 2} = \frac{x}{3} \\ = > \frac{12}{x} = y + 2 \\ = > y = \frac{12}{x} - 2 \\ = > k = \frac{12 - 2x}{x}$