Question

please help with number 3 nd 4

Answer 1

❸ Ans.

✪ Solution :-

• Let the cost of one Senior Ticket be ' x '
• And let the cost of one Child Ticket be ' y '

➛ According to the 1ˢᵗ condition :-

↦ 3x + 3y = $69 ..... ( i )

➛ According to the 2ⁿᵈ condition :-

↦ 5x + 3y = $91 ...... ( ii )

➛ Subtract eq. ( i ) from ( ii ) :-

$\large\textsf{ \: \: \: \: \: \: \: 5x + \cancel{3y} = 91 }\\\large\textsf{ ( - )\: \: \: \: 3x + \cancel{3y} = 69 }\\\large\textsf{-------------------------}\\\large\textsf{2x \: \: \: = 22}\\\\\\\large\textsf{ x = \cfrac{22}{2} }\\\\\\\large\textbf{x = 11}$

➛ Substituting the value of ' x ' in eq. ( i ) :-

$\large: \: \Longrightarrow\textsf{3 ( 11 ) + 3y = 69}\\\\\\\large: \: \Longrightarrow\textsf{33 + 3y = 69}\\\\\\\large: \: \Longrightarrow\textsf{3y = 69 - 33 }\\\\\\\large: \: \Longrightarrow\textsf{ \cancel\cfrac{36}{3} }\\\\\\\large: \: \Longrightarrow\textbf{y = 12 }$

↦ Cost of one Senior Ticket = $11

↦ Cost of one Child Ticket = $ 12

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❹ Ans .

✪ Solution :-

• Let the cost of one Tulip Bulb be ' x '
• And let the cost of one Daffodil Bulb be ' y '

➛ According to the 1ˢᵗ condition :-

↦ 6x + 12 y = $198 ......( i )

➛ According to the 2ⁿᵈ condition :-

↦ 7x + 6y = $127 .......( ii )

➛ Multiply eq. ( ii ) by ' 2 ' :-

↦ 2 ( 7x + 6y ) = 2 × 127

↦ 14x + 12y = 254 .......( iii )

➛ Subtract eq. ( i ) from ( iii ) :-

$\large\textsf{ \: \: \: \: \: 14x +\cancel{12y} = 254 }\\\large\textsf{( - ) \: \: \: 6x + \cancel{12y} = 198 }\\\large\textsf{---------------------}\\\large\textsf{8x\: \: \: \: = 56}\\\\\\\large\textsf{ x = \cancel\cfrac{56}{8} }\\\\\\\large\textbf{x = 7 }$

➛ Substitute the value of ' x ' in eq. ( i ) :-

$\large : \: \Longrightarrow\textsf{6 ( 7 ) + 12y = 198}\\\\\\\large: \: \Longrightarrow\textsf{42 + 12y = 198}\\\\\\\large: \: \Longrightarrow\textsf{12y = 198 - 42 }\\\\\\\large: \: \Longrightarrow\textsf{ y = \cfrac{198}{42} }\\\\\\\large: \: \Longrightarrow\textbf{y = 13}$

↦ Cost of one Tulip Bulb = $7

↦ Cost of one Daffodil Bulb = $13