Question

Please Help with question 4 and 5

Answer 1

density=mass/volume

4)density=59g/7cm^3

=0.059kg/(7×10^-6)m^3

=(59×1000/7)kg/m^3

=8428kg/m^3

5)mass=volume ×density

=50×3.8kg

=190kg

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Answer 2

Answer:

$1 = > \\ cgs \: unit \: of \: density = \\ si \: unit \: of \: density = kgm {}^{ - 3} or \:gmcm {}^{ - 3} \\ \\ 2 = > \\ 16.8 \: gm {cm}^{ - 3} \\ = \frac{16.8 \: gm}{1 \: cm ^{3} } \\ = \frac{(16.8 \div \: 1000) \: kg}{ {10}^{ - 6} {m}^{3} } \\ = \frac{16.8 \times 10 {}^{ - 3} }{10 {}^{ - 6} } kg {m}^{ - 3} \\ = \frac{16.8}{10 {}^{ - 3} } \: kg {m}^{- 3} \\ = 16.8 \times 10 {}^{3} \\ = 16800 \: kg {m}^{ - 3} \\ \\ | |short \: cut = \times {10}^{3} | |$

$3 = > \\ 1709 \: kg {m}^{ - 3 } \\ = \frac{1709}{ {10}^{3} } gmcm^{ - 3} \\ | |short \: cut = \div {10}^{3} | |$

$4 = > \\ m =59 gm \\ v = 7 \: cm\\ we \: know \\ d = \frac{m}{v} = \frac{59}{7} = 8.42857 \: gmcm {}^{ - 3}$

$5 = > \\ d = 3.8 \: kgm {}^{ - 3} \\ v= 50 \: {m}^{3} \\ we \: know \\ m= dv =( 3.8 \times 50) = 190 \: kg$