Question

Please help with this​

Answer 1

Answer:

From the Question we are told that

Mass of A and B is 60kg

Speed of A=2m/s

Speed of B=1m/s

Mass of bag =5kg

Generally the momentum of the astronaut A and bag is mathematically given as

M_A=(60+5)*2M

A

=(60+5)∗2

M_A=130kgm/sM

A

=130kgm/s

Generally to avoid collision the speed of astronaut be should be less than or equal to that of astronaut A with the bag

Therefore for minimum requirement speed of astronaut A should be given by astronaut B's speed which is equal to 1

Therefore

130=(60*1)=(5*v)130=(60∗1)=(5∗v)

V=14m/sV=14m/s