Please help with this math question for my upcoming exam.
Attachments:
Answers
Answered by
1
Hello!!!!
☺️☺️❤️❤️❤️
3sin theta= cos theta
Tan theta=1/3
Tan theta =k
Where k=1/3
In 2nd part ___❤️
3sin^2 2x=cos^2 2x
Tan^2 2x=1/3
Tan2x=1/root3
Tan2x=Tan30°
2x=30
x=15°
#Bebrainly
❤️❤️❤️✌️✌️☺️☺️☺️
☺️☺️❤️❤️❤️
3sin theta= cos theta
Tan theta=1/3
Tan theta =k
Where k=1/3
In 2nd part ___❤️
3sin^2 2x=cos^2 2x
Tan^2 2x=1/3
Tan2x=1/root3
Tan2x=Tan30°
2x=30
x=15°
#Bebrainly
❤️❤️❤️✌️✌️☺️☺️☺️
123oceans:
Tan^2 2x=1/3. could you explain why the 2x still remains , cant it be cancelled out
Answered by
0
Answer:
Please find the attached images.
Step-by-step explanation:
Attachments:
Similar questions