Question

please help with this question

a particle is moving along x axis
x= (3t^2-2t^3)
find

A) it's average velocity t=0s and t=2s
B) v(t) and a (t)
C) the time at which it's acceleration is zero and find its velocity at the instant.
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Answer 1

Answer:

hope it helps you%%%%%

Explanation:

given x=3t^2-2t^3   a] velocity =ds/dt=0 therefore the average velocity=0 and i perfectly cnt understand the question