Question

Please help yaar it's urgent I have to this work in tuition
Ch - Real Numbers
Class 10th
Don't even try to post irrevalent answers otherwise your 10 answers will be reported​

Answer 1

Answer:

A.T.Q,

The number leaves 3 as remainder.

So, 144 - 3 = 14

180 - 3 = 177

192 - 3 = 189

Now,

HCF of 141, 177 and 189 is 3.

And according to question It leaves remainder 3 in each case.

141 = 23 * 6 + 3

177 = 29 * 6 + 3

189 = 31 * 6 + 3

Thus, 6 is the number.

Hope it is helpful (•‿•)...