PLEASE HELPP WILL MARK BRAINLIEST
Solve numbers 10 – 18 using the elimination method. Show your work.
10. y = (2/3)x - 1
y = -x + 4
11. x + y = 0
3x + y = -4
12. 4x + 3y = -15
y = x + 2
13. x + 2y = -4
4y = 3x + 12
14. y = 2x
x + y = 3
15. x = 3 - 3y
x + 3y = -6
16. y = -2x + 1
y = x - 5
17. y = (1/2)x - 3
y = (3/2)x – 1
18. x + y = 2
4y = -4x + 8
Answers
Here are some answers. Please recheck it after a while. I'll add the rest of the equations.
10. y=2x/3 -1
y= -x+4
=> 2y= (2x/3) -x + 3 [Addition]
=> 2y= (2x–3x+9)/3
=> 2y= (–x+9)/3
=> y= (–x+9)/6
Now, (ii):
–x+9/6= –x+4
–x+9= –6x+24
=>x= 3
(i):
y=6/3 –1= 1
______________
11. (i)–(ii)
–2x= 4
=> x= –2
(i):
–2+y=0
=> y= 2
______________
12. multiplying (ii) by 4 we get –4x+4y=8
(i)+(ii)
7y= –7
=> y= –1
(ii):
–4x+4(–1)=8
=> x= –3
______________
13. x + 2y = -4
4y = 3x + 12 => –3x+4y=12
(i)×3 then (i)+(ii):
10y=0
y= 0
(i):
x+2.0=–4
=> x= –4
_____________
14. y = 2x
x + y = 3
i–ii:
–3x= –3
=> x= 1
(i):
y= 2
____________
16. y = -2x + 1
y = x - 5
(i)–(ii):
x= –4
(i):
y= –2(–4)+1= 9
____________
17. y = (1/2)x - 3 => y–x/2= –3...(i)
y = (3/2)x – 1 => y–3x/2= –1...(ii)
(i)–(ii):
(3x–x)/2=–2
=> x= –2
(i): y–(–2/2)= –3
=> y= –4
____________
*18. x + y = 2
4y = -4x + 8
Multiplying (i) by 4 and then (i)+(ii):
8x+8y= 10
=> 8x= 10–8y
=> x= (10–8y)/8...(iii)
Now, substitute (iii) into (i):
(10–8y)/8 + y=2
=> (10–8y+8y)/8=2
=> 0= 6 [Not possible]
______________________
*15. x = 3 - 3y => x+3y=3...(i)
x + 3y = -6...(ii)
If (i)–(ii):
0= 9 [Not possible]
Or if (i)+(ii):
2x+6y= –3
Now substitute here the value for x feom the first line which is x=3-3y
2(3–3y)+6y= –3
=> 6–6y+6y= –3
=> 6=–3 [Not possible]
________________________________
P.S.
*There is no solution for these (15, 18) equations.
Answer:
For example, if a dice is rolled 6000 times and the number '5' occurs 990 times, then the experimental probability that '5' shows up on the dice is 990/6000 = 0.165. For example, the theoretical probability that the number '5' shows up on a dice when rolled is 1/6 = 0.167