Question

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An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror. What is the magnification? Is the mirror concave or convex?​

Answer 1

Answer :-

→ Magnification is + 0.4 .

→ The mirror is a convex mirror .

Explanation :-

We have :-

• Distance of the object = 5 m

• Distance of the image = 2 m

______________________________

From sign convention, we have :-

• u = -5 m

From the formula of magnification of a spherical mirror :-

m = -(v/u)

Where :-

• m is Magnification.

• v is distance of image.

• u is distance of object.

⇒ m = -(2/-5)

⇒ m = -(-0.4)

⇒ m = + 0.4

______________________________

Now we understand that :-

→ The magnification is positive.

→ Image is erect and diminished.

From above properties, we can say that the mirror is a convex mirror.

Answer 2

Answer:

Given :-

• An object is kept at a distance of 5 m in front of a spherical mirror, which forms its erect image at a distance of 2 m from the mirror.

To Find :-

• What is the magnification.
• Which type of mirror it is.

Formula Used :-

$\clubsuit$ Magnification Formula :

$\longmapsto \sf\boxed{\bold{\pink{Magnification\: (m) =\: \dfrac{- v}{u}}}}$

where,

• v = Image Distance
• u = Object Distance

Solution :-

Given :

• Object Distance (u) = - 5 m
• Image Distance (v) = 2 m

According to the question by using the formula we get,

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{- 2}{- 5}$

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{\cancel{-} 2}{\cancel{-} 5}$

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{2}{5}$

$\longrightarrow \sf\bold{\red{Magnification\: (m) =\: 0.4}}$

$\therefore$ The magnification is 0.4.

Now, we have to find which type of mirror it is :

As we can notice that :

• The image is virtual and erect.
• The magnification has positive sign (+ ve).

$\therefore$ The image is a convex mirror.