Question

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Answer 1

Answer:

Step-by-step explanation:

∠B = ∠E

BC = DE

∠1 = ∠2

Hence,  △ABC = △AED by A.A.S test

Hence, AD = AC (congruent parts of congruent triangle are congruent)

Therefore, in △ACD

∠C = ∠D (As △ACD is an isosceles triangle as AC = AD)

Therefore, ∠BDA = ∠ECA

Hence proved

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