Question

please hep me its urgent ​

Answer 1

Step-by-step explanation:

Given :-

3^(3x-1) ÷ 9 = 27

To find :-

Find the value of x ?

Solution :-

Given equation is 3^(3x-1) ÷ 9 = 27

It can be written as

=> 3^(3x-1) ÷ (3^2) = 27

=> 3^(3x-1) / (3^2) = 27

=> 3^[(3x-1)-2] = 27

Since a^m / a^n = a^(m-n)

=> 3^(3x-1-2) = 27

=> 3^(3x-3) = 27

=> 3^(3x-3) = 3×3×3

=> 3^(3x-3) = 3^3

=> 3x-3 = 3

Since the bases are equal then exponents must be equal.

=> 3x = 3+3

=> 3x = 6

=> x = 6/3

=> x = 2

Therefore , x = 2

Solution:-

The value of x for the given problem is 2

Check:-

If x = 2 then LHS of the given equation

LHS = 3^(3x-1) / 9

=> 3^(3×2-1)/9

=> 3^(6-1)/9

=> 3^5/9

=>3^5/3^2

=> 3^(5-2)

=> 3^3

=> 3×3×3

=> 27

=> RHS

LHS = RHS is true for x = 2

Used formulae:-

• a^m / a^n = a^(m-n)
• If the bases are equal then exponents must be equal.