Question

please hlp me to find out the ans

Answer 1

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Answer 2

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

We notice, That the Rationalising Factor of the Denominator is $\sqrt{3} + \sqrt{2}$

Hence,

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} + \sqrt{2}} \\ = \frac{ {( \sqrt{3} + \sqrt{2} )}^{2} }{ (\sqrt{3} - \sqrt{2})(\sqrt{3} + \sqrt{2})} \\ = \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ = \frac{5 + 2 \sqrt{6} }{1} \\ = 5 + 2 \sqrt{6}$

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