Question

please ho sake to solve kr k ans vejna​

Answer 1

Explanation:

Ksp (AgCl) = [Ag+] [Cl-]

[Ag+] = (1.8*10^-10)/(0.10)

[Ag+] = 1.8*10^-9 M

Ksp(PbCl2) = [Pb+2][Cl-]^2

(1.7*10^-5)/(0.10)^2 = [Pb+2]

[Pb+2] = 1.7*10^-3 M

So the Option A is correct.......