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Join AB
Angle ADB=angleCDE=90
By Pythagorean’s theorem
AB^2=AD^2+DB^2
5^2-4^2=AD^2
AD=3cm
If chord intersect each other internally then
AD*DE=DC*DB
3*DE=9*4
DE=12cm
AE=AD+DE
AE=3+12
AE=15cm
Angle ADB=angleCDE=90
By Pythagorean’s theorem
AB^2=AD^2+DB^2
5^2-4^2=AD^2
AD=3cm
If chord intersect each other internally then
AD*DE=DC*DB
3*DE=9*4
DE=12cm
AE=AD+DE
AE=3+12
AE=15cm
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