Question

please I am so confused please give the right answer of the question​

Answer 1

Answer:

This is quadratic if maximum power of x is 2 here .

or it is in form

$a {x}^{2} + bx + c = 0 \: \: \: \: where \: \: \: a \neq0$

Simplify

$(x + 2) {}^{3} = 2x( {x}^{2} - 1) \\ {x}^{3} + 8 + 6x(x + 2) = 2 {x}^{3} - 2x \\ {x}^{3} - {x}^{2} - 14x - 8 = 0$

Maximum power of x is 3

So it is cubic not quadratic

Answer 2

Answer:

This is quadratic if maximum power of x is 2 here .

or it is in form

a {x}^{2} + bx + c = 0 \: \: \: \: where \: \: \: a \neq0ax

2

+bx+c=0wherea



=0

Simplify

\begin{gathered}(x + 2) {}^{3} = 2x( {x}^{2} - 1) \\ {x}^{3} + 8 + 6x(x + 2) = 2 {x}^{3} - 2x \\ {x}^{3} - {x}^{2} - 14x - 8 = 0\end{gathered}

(x+2)

3

=2x(x

2

−1)

x

3

+8+6x(x+2)=2x

3

−2x

x

3

−x

2

−14x−8=0

Maximum power of x is 3

So it is cubic not quadratic