Question

PLEASE I BEG U NO SPAM

Answer 1

Answer:

33》(–2a² – 7b² – c² – 11d + 6)

34》3⁶³

Step-by-step explanation:

33》

Let quantity "x" is to be subtracted

So, as per the question —

(3a² + 4b² + c² + 6d – 7) – x = (a² + 2c² – 3b² – 1 – 5d)

or,

x = (a² + 2c² – 3b² – 1 – 5d) – (3a² + 4b² + c² + 6d – 7)

or,

x = (a² + 2c² – 3b² – 1 – 5d – 3a² – 4b² – c² – 6d + 7)

or,

x = (–2a² – 7b² – c² – 11d + 6)

It can also be written as (taking minus common) —

x = – (2a² + 7b² + c² + 11d – 6)

So, value to be subtracted = (–2a² – 7b² – c² – 11d + 6)

34》

$\frac{ { ({3}^{7}) }^{8} \times { ({9}^{2} )}^{4} }{ {27}^{3} } = \frac{ {3}^{56} \times {9}^{8} }{ {27}^{3} }$

Converting all bases to 3 —

$\frac{ {3}^{56} \times { ({3}^{2}) }^{8} }{ { ({3}^{3}) }^{3} } = \frac{ {3}^{56} \times {3}^{16} }{ {3}^{9} }$

When multiplied, the powers add —

$\frac{ {3}^{(56 + 16)} }{ {3}^{9} } = \frac{ {3}^{72} }{ {3}^{9} }$

When divided, the powers subtract —

${3}^{(72 - 9)} = {3}^{63} \: \: (ans)$

Hope this helps you :)

Answer 2

Answer: $2a^{2}+7b^{2}-c^{2}+11d-6$

Step-by-step explanation: