Question

please.. I'll mark you as the brainlyest... please​

Answer 1

Answer:

Step-by-step explanation:

Proof:

We take ΔABE and ΔACF.

In ΔABE and ΔACF,

⇒ ∠AEB = ∠AFC

⇒ ∠A = ∠A

⇒ AB = AC

⇒ ∴ ΔABE ≅ ΔACF ( AAS congruence rule )

⇒ BE = CF

Hence proved.

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